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# 7 58 An adiabatic pump is to be used to compress saturated

### 7 58 An adiabatic pump is to be used to compress saturated ...

7–58 An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure to 15 MPa in a reversible manner. Determine the work input using (a)

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### Solved: An adiabatic pump is to be used to compress ...

An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure to 15 MPa in a reversible manner. Determine the work input using (a)

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### An adiabatic pump is to be used to compress saturated ...

Mar 01, 2018  An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure to 15 MPa in a reversible manner. Determine the work input using (a)

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### SOLVED:An adiabatic pump is to be used to compress ...

An adiabatic pump is to be used to compress saturated liquid water at 10 \mathrm{kPa} to a pressure to 15 \mathrm{MPa} in a reversible manner. Determine the

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### Solved: 7-62 An Adiabatic Pump Is To Be Used To Compress S ...

7-62 An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure to 15 MPa in a reversible manner. Determine the work input

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### Homework 9: Due Friday, April 9, 6 PM

7. An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure of 15 MPa in a reversible process. Compare the calculated work output in kJ/kg by three methods: a. Using entropy and enthalpy data from the compressed liquid water table (A-7) b. Inlet specific volume value and pressure values given c.

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### [Solved] An adiabatic pump is to be used to compress ...

An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure to 15 MPa in a reversible manner. Determine the work input using. (a) Entropy data from the compressed liquid table, (b) Inlet specific volume and pressure values, (c) Average specific volume and pressure values. Also, determine the errors involved in ...

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An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure to 15 MPa in a reversible manner. Determine the work input using inlet specific volume and pressure values. Refrigerant-134a at 140 kPa and –10°C is compressed by an adiabatic 0.5-kW compressor to an exit state of 700 kPa and 60°C.

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### ThermoFinalReview.docx - 1 A vapor-compression ...

An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure to 15 MPa in a reversible manner. Determine the work input using (a) the compressed liquid table,(b) inlet specific volume and pressure values, (c) average specific volume and pressure values.(15.10 kJ/kg, 15.14 kJ/kg, 15.10 kJ/kg)

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### SOLVED:A reversible adiabatic flow of liquid wate

An adiabatic pump is to be used to compress saturated liquid water at $10 \m 02:38 Water at 20 psia,$240 \mathrm{F}$, receives$40 \mathrm{Btu} / \mathrm{lbm}

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### Adiabatic Compression in a Pump — Collection of Solved ...

Jun 24, 2019  Solution. First, we express the ratio of the initial volume V 0 and the final volume V of the air in the pump. Let's denote the unknown area of the base of the cylinder by A. Then the following holds true: V 0 V = l A ( l − d) A = l ( l − d). Quick compression can be considered to be an adiabatic process, and Poisson's equation can be ...

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### SOLUTIONS: HOMEWORK #6

HOMEWORK ASSIGNMENTS 6, 7 and 8 5-79 Steam expands in a turbine. The change in kinetic energy, the power output, and the turbine inlet area are to be determined. Assumptions 1 This is a steady-flow process since there is no change with time. 2 Potential energy changes are negligible. 3 The device is adiabatic and thus heat transfer is negligible.

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### Thermodynamics An Engineering Approach

5–56 Refrigerant-134a enters an adiabatic compressor as saturated vapor at -24°C and leaves at 0.8 MPa and 60°C. The mass flow rate of the refrigerant is 1.2 kg/s. Determine (a) the power input to the compressor and (b) the volume flow rate of the refrigerant at the compressor inlet. Solution

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The mathematical equation for an ideal gas undergoing a reversible (i.e., no entropy generation) adiabatic process can be represented by the polytropic process equation =, where P is pressure, V is volume, and for this case n = γ, where = = +, C P being the specific heat for constant pressure, C V being the specific heat for constant volume, γ is the adiabatic index, and f is the number of ...

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### AME 50531: Intermediate Thermodynamics Homework Solutions

2.4 Problem 4: 12.97 Consider an ideal air-standard Stirling cycle with an idealregenerator. The minimum pressure and tmeperature in the cycle are 100 kPa, 25 C, the compression ratio is 11, and the maximum temperature in the cycle is 1000 C. Analyze each of the four processes in this cycle for work and heat transfer, and determine the overall perfomance of the engine.

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### ENGR 2010 Thermodynamics I: HW set 10 isentropic eﬃciency ...

4. Air enters a adiabatic turbine at 1200 K and 8 atm pres-sure. The exit pressure is 1 atm. The turbine has an isentropic eﬃciency of 0.85. Determine the actual exit temperature and the work per unit mass. Use the air tables to solve this problem. From the air tables at 1200 K, h1 =

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### Chapter 7

Example 7.2-47----- Refrigerant 134a is the working fluid in an ideal vapor-compression refrigeration cycle that communicates thermally with a cold region at - 10°C. Saturated vapor enters the compressor at - 10°C and saturated liquid leaves the condenser at 9 bar.

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### A review on design criteria for vortex tubes

Aljuwayhel et al. [58], Skye et al. [59], Eiamsa-ard and ... By analogy the work used to compress the Heat Mass Transfer (2009) 45:613–632 615 123. ... cr ¼ k k 1 eðÞT in T c T in ln p in p c ð13Þ The coefﬁcient of performance (COP) for a heat pump is S_ m_ m: vortex tubes vortex tubes vortex tubes.

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### 7.6. Rankine cycle EME 812: Utility Solar Power and ...

7.6. Rankine cycle. 7.6. Rankine cycle. We are going to overview the principle of thermodynamic cycle operation using Rankine cycle example, since most of solar power cycles currently operating are Rankine cycles. The Rankine cycle system consists of a pump, boiler, turbine, and condenser. The pump delivers liquid water to the boiler.

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### (Solved) - An adiabatic pump is to be used to compress ...

Jan 25, 2021  An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure to 15 MPa in a reversible manner. Determine the work input using (a) entropy data from the compressed liquid table, (b) inlet specific volume and

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### SOLVED:A reversible adiabatic flow of liquid wate

An adiabatic pump is to be used to compress saturated liquid water at $10 \m 02:38 Water at 20 psia,$240 \mathrm{F}$, receives$40 \mathrm{Btu} / \mathrm{lbm}

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### Horsepower Required for Compressing Air - Womack Machine ...

Figures are HP to compress 1 SCFM from 0 PSIG to the pressures shown. Calculate required SCFM from information in Design Data Sheet 58 and multiply times figure in the table. Adiabatic Compression. This is defined as compression which takes place without allowing the

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### Conservation of mass

600 °C, 5 MPa.The steam expands in the turbine to a saturated vapor at 500 kPa where 8% of the steam is removed for some other use. The remainder of the steam continues to expand all the way to the turbine exit where the pressure is now 10kPa and quality is 88%. The turbine is assumed to be adiabatic.

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### PHYS 221 SI Worksheet - Iowa State University

(19.59) An air pump has a cylinder 0.250 m long with a movable piston. The pump is used to compress air from the atmosphere (at absolute pressure 1.01E5 Pa) into a very large tank at 4.20E5 Pa gauge pressure. (For air, CV = 20.8 J/molK.) (a) The piston begins the

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### A review on design criteria for vortex tubes

Aljuwayhel et al. [58], Skye et al. [59], Eiamsa-ard and ... By analogy the work used to compress the Heat Mass Transfer (2009) 45:613–632 615 123. ... cr ¼ k k 1 eðÞT in T c T in ln p in p c ð13Þ The coefﬁcient of performance (COP) for a heat pump is S_ m_ m: vortex tubes vortex tubes vortex tubes.

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### Could an air compressor be used to compress steam ...

One practical problem, if it's saturated steam, is that by increasing pressure, you're increasing the condensation point, so a lot of the steam will keep turning to liquid water without any considerable pressure growth.If you take 10l of dry air at 1 bar and compress it to 2 bar, you get about 5l of the compressed air. But if you take saturated steam - you'll get a glass of water at a little ...

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Example of Adiabatic Expansion Assume an adiabatic expansion of helium (3 → 4) in a gas turbine (Brayton cycle). Assume an adiabatic expansion of helium (3 → 4) in a gas turbine.Since helium behaves almost as an ideal gas, use the ideal gas law to calculate outlet temperature of the gas (T 4,real).In this turbines the high-pressure stage receives gas (point 3 at the figure; p 3 = 6.7 MPa ...

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### Solutions manual chapter 7 (1) - SlideShare

Dec 08, 2015  Borgnakke and Sonntag 7.60 A heat pump receives energy from a source at 80oC and delivers energy to a boiler that operates at 350 kPa. The boiler input is saturated liquid water and the exit is saturated vapor both at 350 kPa. The heat pump is driven by a 2.5 MW motor and has a COP that is 60% of a Carnot heat pump COP.

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### The First Law of Thermodynamics : The First Law Applied to ...

Oct 28, 2014  4.7 The First Law Applied to Control Volumes. We have thus far restricted ourselves to systems; no mass crosses the boundary of a system. This restriction is acceptable for many problems of interest and may, in fact, be imposed on the power plant schematic shown in Fig. 4.3.

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### Engineering

Apr 09, 2015  Development of Hartwick, W. (Chemical Engineering, Oct, 1956) indicates an approach to correcting the ideal gas horsepower for the effects of compressibility. Determine gas specific volume at inlet conditions: v = ZRT / (144 P) ft3/lb. Obtain Z from compressibility charts, (or for specific gas or

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### (PDF) EXAMPLE 8–15 Second-Law Analysis of a Steam Turbine ...

458 EXERGY 3 MPa 450°C 300 kW EXAMPLE 8–15 Second-Law Analysis of a Steam Turbine Steam enters a turbine steadily at 3 MPa and 4508C at a rate of 8 kg/s and exits at 0.2 MPa and 1508C, (Fig. 8–44). The steam is losing heat to the sur- ˙ W rounding air at 100 kPa and 258C at a rate of 300 kW, and the kinetic and potential energy changes ...

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### US3759348A - Method of compressing chlorine gas - Google ...

US3759348A US3759348DA US3759348A US 3759348 A US3759348 A US 3759348A US 3759348D A US3759348D A US 3759348DA US 3759348 A US3759348 A US 3759348A Authority US United States Prior art keywords compressor chlorine gas temperature liquid Prior art date 1971-11-08 Legal status (The legal status is an assumption and is not a legal conclusion.

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### Chapter 10: Refrigeration Cycles

Chapter 10-5 The P-h diagram is another convenient diagram often used to illustrate the refrigeration cycle. The ordinary household refrigerator is a good example of the application of this cycle. Results of First and Second Law Analysis for Steady-Flow

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